问题详情:
如图所示,在汶川大地震中,一架直升飞机在灾区某地上空做定点空投救灾物资,已知由静止释放的一包物资,经5s刚好着地,忽略空气阻力的作用g=10 m/s2.求:
(1)释放后1s末物资速度大小.
(2)直升飞机距离地面的高度.
(3)物资落地前最后1s内的位移.
【回答】
解:物资的下落看作自由落体运动。
(1)由····························(2分)
得:·························(1分)
(2)由···························(2分)
得:·························(1分)
(3)··························(3分)
得:··························(1分)
用其他方法解答正确同样得分。
知识点:自由落体运动
题型:计算题